if Statement...

cengiz · #1 (**permalink**) 07-13-2005

...doesnt work

my Code

Code:

MOD=`expr $count % 2`
if ($MOD == 0) then echo "example"

in the prompt it prints me: ksh: syntax error: 'if' unmatched

why this problem?

I've tried already

if (($count ==0 )) # it doesnt work
and wit [] nad [[]] #it doesnt work too

matrixmadhan · #2 (**permalink**) 07-13-2005

try this,

if [ $MOD = 0 ]; then echo "example"

cengiz · #3 (**permalink**) 07-13-2005

when i try your code the pormpt prints: then unmatched

vino · #4 (**permalink**) 07-13-2005

Quote:

Originally Posted by matrixmadhan

try this,

if [ $MOD = 0 ]; then echo "example"

Try this

if [ $MOD = 0 ]; then
echo "example"
fi;

Vino

vino · #5 (**permalink**) 07-13-2005

Quote:

Originally Posted by matrixmadhan

try this,

if [ $MOD = 0 ]; then echo "example"

Try this

Code:

if [ $MOD = 0 ] ; then 
echo "example"
fi ;

Vino

cengiz · #6 (**permalink**) 07-13-2005

Quote:

Originally Posted by vino

Try this

Code:

if [ $MOD = 0 ] ; then 
echo "example"
fi ;

Vino

it just prints me: ksh: syntax error: 'then' unmatched

cengiz · #7 (**permalink**) 07-13-2005

I've solved this problem and indeed

Code:

if [ $MOD -eq 0 ] ; then
  echo "ja" ;
fi

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