process already exists - Shell Programming and Scripting

kadishmj · #1 06-13-2005

I'm attempting to modify a script that ftps files from one machine to another (see this post ). I've been testing it a few times, and once I had to kill the test because it was taking forever, and I know it wasn't working. Now, when I try to test the script again, I'm getting the following:

$ ./move_logs_test3.sh
./move_logs_test3.sh[18]: process already exists

As a result, I can't test my script.

-How do I determine what this process is?
-How do I remove it?
-How do I prevent this from happeneing again?

Thanks for your help!

reborg · #2 06-13-2005

Post the script exactly as you have it. The line number does not tally with the script you referenced. It is most likely that your ftp co-proccess is still running.

kadishmj · #3 06-13-2005

My code is below. If the ftp co-process is still running, how would I end it?

Code:

#! /usr/bin/ksh

HOST=hostname
USER=user1
PASSWD=password
#logdir="/opt/system_logs"
logdir="/export/home/user1"

exec 4>&1
ftp -nv >&4 2>&4 |&

for SERVER in server1 server2 server3
do
   cd $logdir/$SERVER

   for FILENAME in `find . -type f -name "access_log*" -mtime 0 -print | sed 's/^\.\///'`
   do
      exec 4>&1
      ftp -nv >&4 2>&4 |&
      print -p open $HOST
      print -p user $USER $PASSWD
      print -p lcd  $logdir/$SERVER
      print -p cd $SERVER
      print -p bin
      print -p put $FILENAME
      print -p bye

      wait
      exit 0
   done
done

Just Ice · #4 06-13-2005

try running the script without the red lines ... if that doesn't work still, make sure your find command gives you a definite list and doesn't go into an infinite loop ...

... if you have to kill the process --- look for ftp and/or find as that's where it's most likely to hang ...

Quote:

Originally Posted by kadishmj

My code is below. If the ftp co-process is still running, how would I end it?

Code:

#! /usr/bin/ksh

HOST=hostname
USER=user1
PASSWD=password
#logdir="/opt/system_logs"
logdir="/export/home/user1"

exec 4>&1
ftp -nv >&4 2>&4 |&

for SERVER in server1 server2 server3
do
   cd $logdir/$SERVER

   for FILENAME in `find . -type f -name "access_log*" -mtime 0 -print | sed 's/^\.\///'`
   do
      exec 4>&1
      ftp -nv >&4 2>&4 |&
      print -p open $HOST
      print -p user $USER $PASSWD
      print -p lcd  $logdir/$SERVER
      print -p cd $SERVER
      print -p bin
      print -p put $FILENAME
      print -p bye

      wait
      exit 0
   done
done

Perderabo · #5 06-14-2005

Also note that "exit 0" causes the script to terminate. Placed inside the loop like that, you will end the script on the first iteration of the loop. Move "exit 0" to the end of the script. On the other hand, leave "wait" exactly where it is. The "wait" makes the script pause until the ftp co-process has exited.

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