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Old 06-26-2012
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awk and get a part of field ?

I have a list of log.txt, thisis a flatfile separate by a pipe |

Code:
2012/06/23 18:58:15 |    4:sabercats   pid=020272 opened Boards 0, 1, 2, 3 for /home/directory_germany/germany/location/qt/NET12/full_111_ddr5_soq523_2X_FV_4BD_PD3_0.qt/dbFiles/germany.proto	|berlin|test1|test2
2012/06/25 17:40:56 |  168:sabercats   pid=004319 opened Boards 0,2 for /home/directory_england/england/location/qt/NET06/full_2X_FV_1BD_PD3_.qt/dbFiles/england.proto	|cambridge|test1|test2
2012/06/26 15:14:02 |  146:sabercats   pid=014780 opened Boards 0, 1, 2, 3 for /home/directory_spain/spain/location/qt/NET08/full_111_sddr3_soq523_2X_FV_4BD_PD3_2.qt/dbFiles/spain.proto	|madrix|test3|test4
2012/06/26 10:47:35 |   44:sabercats   pid=019276 opened Boards 0, 1, 2, 3 for /home/directory_spain/spain/location/qt/NET08/full_111_sddr3_soq523_2X_FV_4BD_PD3_1.qt/dbFiles/spain.proto	|barcelona|test5|test6

How do we run awk and get a new file with location.txt and separate field by a comma or pipe and the results should be:

Code:
germany,NET12/full_111_ddr5_soq523_2X_FV_4BD_PD3_0.qt,berlin
england,NET06/full_2X_FV_1BD_PD3_.qt,cambridge
spain,NET08/full_111_sddr3_soq523_2X_FV_4BD_PD3_2.qt,madrix
spain,NET08/full_111_sddr3_soq523_2X_FV_4BD_PD3_1.qt,barcelona

Thanks for replying.
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Old 06-26-2012
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How about:
Code:
awk -F'[/|]' '{ print $7","$10"/"$11","$14}' infile

or:
Code:
awk -F'[/|]' '{gsub(/.*directory_/,"");print $1","$(NF-6)"/"$(NF-5)","$(NF-2)}' infile

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Old 06-27-2012
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Thanks, it works.
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