pattern matching and print with sed

nymus7 · #1 (**permalink**) 04-14-2005

Hi
It is possible with sed to print a pattern within a line matching regexp?
So, the line looks like : 19:00:00 [56434] blablablabla jobid 2345 <2>
the regexp is "jobid 2345" and the pattern is 56434.
That the code for find the line:

Code:

sed -n"/jobid 2345/p"

I've tries that but it doesn't run

Code:

sed -n"/jobid 2345/,/\[.*\]/p"

But how to include in my code the right expression to print only the pattern 56434 from that line?
I could perhaps use other utilities like grep or awk but i want to do that with sed!
nymus7

Perderabo · #2 (**permalink**) 04-14-2005

sed -n "/jobid 2345/s/.*\[\(.*\)\].*/\1/p"

nymus7 · #3 (**permalink**) 04-14-2005

Hi
It's working...

Thanks a lot

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