ksh: A part of variable A's name is inside of variable B, how to update A?

pa3be · #1 (**permalink**) 03-28-2005

This is what I tried:

vara=${varb}_count
(( vara += 1 ))

Thanks for help

vgersh99 · #2 (**permalink**) 03-28-2005

Quote:

Originally Posted by pa3be

This is what I tried:

vara=${varb}_count
(( vara += 1 ))

Thanks for help

hmm.... this is one confusing explanation.
what are you trying to do?

pa3be · #3 (**permalink**) 03-28-2005

I'm iterating through a list of test names, each has two associated variables: the number of times the test passed, and the number of times the test ran

varb would be the name of the test at the current iteration (e.g. test04)

when I check if the test passed, I need to increment the corresponding count variable (for example, if at this iteration the test name is test04, the associated count variable name is test04_count)

Thus, the name of the variable to be incremented is composed from the value of one variable (varb) and "_count"

The question is how to increment that variable (vara)

vgersh99 · #4 (**permalink**) 03-28-2005

here's something to start with as I'm still a bit confused....

Code:

#!/bin/ksh

typeset num;

for iter in 1 2 3 4 5 6 7 15 123
do
   varb="test$(printf "%02d" ${iter})"
   vara="${varb}_count"
   # increment vara
   #
   num=$(printf "%02d" $(( $(echo "${vara}" | sed -e 's/^[^0-9]*\([0-9][0-9]*\)_.*/\1/') + 1 )) )
   echo "varb->[${varb}] vara->[${vara}] incrementedNum->[${num}] incrementedVarA->[test${num}_count]"
done;

pa3be · #5 (**permalink**) 03-30-2005

after some adjustments, I got what I needed.

Thanks a lot.

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