incrementing a for loop

run_time_error · #1 (**permalink**) 03-27-2005

I have,

LIST="a b c d e"
for word in $LIST
do
echo $word
done

would give me
a
b
c
d
e

With the first iteration of the for loop, I get "a" as the result.
Is it possible that I get both "a" and "b" in only the first iteration.
In the next iteration I get "c" and "d" and so on.
I hope I am clear enough!!
Thanks

Perderabo · #2 (**permalink**) 03-27-2005

Interesting that you have an odd number of elements. It's not clear how to handle that final e. But you could do something like this:

Code:

$ cat loop
#! /usr/bin/ksh

LIST="a b c d e"
switch=1
for word in $LIST  ; do
        if ((switch)) ; then
                word1=$word
        else
                word2=$word
                echo word1 = $word1 word2 = $word2
        fi
        ((switch=!switch))
done

exit 0
$ ./loop
word1 = a word2 = b
word1 = c word2 = d
$

muthukumar · #3 (**permalink**) 03-28-2005

Quote:

Originally Posted by run_time_error

I have,

LIST="a b c d e"
for word in $LIST
do
echo $word
done

would give me
a
b
c
d
e

With the first iteration of the for loop, I get "a" as the result.
Is it possible that I get both "a" and "b" in only the first iteration.
In the next iteration I get "c" and "d" and so on.
I hope I am clear enough!!
Thanks

You can accomplish as,
# echo $LIST | awk '{ for (i=1;i<=NF;i++) { printf $i" "; if (i%2==0) { printf "\n"} } }END { printf "\n" }'
a b
c d
e
#

HTH.

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