awk doubt..

esham · #1 (**permalink**) 03-13-2005

Hello,

Iam trying to get the IP of the hostname of the machine from /etc/hosts.
I used the command as below:

Quote:

awk "/$(hostname)/ {print $1}" /etc/hosts

But the result shows the IP with the hostname..
like

192.168.0.8 test12111.com

I need to get only 192.168.0.8

Please help
Thanks in advance
esham

vgersh99 · #2 (**permalink**) 03-13-2005

Code:

nawk -v i=$(hostname) '$0 ~ i {print $1}' /etc/hosts

tanku · #3 (**permalink**) 03-13-2005

another way,

cat /etc/hosts|grep $HOSTNAME|awk '{print $1}'

vgersh99 · #4 (**permalink**) 03-13-2005

Quote:

Originally Posted by tanku

another way,

cat /etc/hosts|grep $HOSTNAME|awk '{print $1}'

UUOC

grep "${HOSTNAME}" /etc/hosts |awk '{print $1}'

tanku · #5 (**permalink**) 03-13-2005

it's not useless! it's clean

vgersh99 · #6 (**permalink**) 03-13-2005

Quote:

Originally Posted by tanku

it's not useless! it's clean

#define clean ???

esham · #7 (**permalink**) 03-13-2005

Thanks for all replies..
All worked great..

But let me know what made my script wrong..

Quote:

awk "/$(hostname)/ {print $1}" /etc/hosts

anybody please explain...

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