Hi all,

I use the diff command and got the output:

$> diff -e file1.txt file2.txt
15a
000675695	Yi Chen	Chen	200520	EASY	50	2/28/05 0:00	SCAD Debit Card Charge
.
12a
000731176	Sarah	Anderson	200520	EASY	25	2/28/05 0:00	SCAD Debit Card Charge
.
11a
000624694	Meagan	Thomas	200520	EASY	402	2/28/05 0:00	SCAD Debit Card Charge
000679538	Nicole	Blackmon	200520	EASY	750	2/28/05 0:00	SCAD Debit Card Charge
.
2a
000679668	Ashley	Tucker	200520	EASY	200	2/28/05 0:00	SCAD Debit Card Charge
000672299	Candace	Daniels	200530	EASY	100	2/28/05 0:00	SCAD Debit Card Charge
.

If I understand your question correctly, you just want to be left with a the list of rows that need to be added to file1 in order to make it identical to file2, and you don't care about the actual position of these rows within the output (as you want to remove the 15a, 11a, etc...)?

If so, pass the output through sed

diff -e file1.txt file2.txt | sed -e '/^\.$/d' -e '/^[0-9][0-9]*a$/d'

zazzybob,

Thanks for your response, that's exactly what i am looking for
But i was just wondering, if i want the output in the actual position of these row within the output file, what is the code like? for instant, i want to get rid of those lines with 1a2,3, 4a7, 7a11, 10a15 and the ">" in front of the line.

$ > diff 1.txt 2.txt
1a2,3
> 000685115     Ariel   Wilchek 200520  EASY    150     2/28/05 0:00    SCAD Deb
it Card Charge
> 000686937     Charles Payne   200520  EASY    200     2/28/05 0:00    SCAD Deb
it Card Charge
4a7
> 000735567     Hayden  Lewis   200520  EASY    50      2/28/05 0:00    SCAD Deb
it Card Charge
7a11
> 000701166     Kyle    Provencal       200520  EASY    500     2/28/05 0:00
SCAD Debit Card Charge
10a15
> 000014514     Tiffany Jennings        200520  EASY    65      2/28/05 0:00
SCAD Debit Card Charge

Try as,

diff 1.txt 2.txt | sed '/^[0-9]a.*$/d;s/^>[ ]//'

HTH.

diff file1.txt file2.txt | sed -e '/^[0-9][0-9a,]*$/d' -e 's/> //'

hey guys,

Thanks alot.....

CT