Hey guys:

I've been meaning to post this question for awhile...it is regarding grep. Let's say for example that the following entry is in logxx:

Wed Feb 2 07:44:11 <vsm> 91030 Line 5 Severity 1 Vps 6
Call Answered - DN:8753101 CLID:5164665761 PI:83

If I do a grep 91030 logxx, I will get the following:

Wed Feb 2 07:44:11 <vsm> 91030 Line 5 Severity 1 Vps 6

However, what I really want are BOTH lines. Is there a way to grep and have it return both lines??

Thanks,

-cd

Pls dont mind if this code seems stupid:

grep -i 91030 logxx >> file
grep -v 91030 logxx >> file

Thanks for the attempt, but that did not do the trick.

-cd

Please try:

grep -A1 91030 logxx

generic:

grep -A1 PATTERN [FILE...]

That did not work either. Here's the error:

grep: illegal option -- A
grep: illegal option -- 1
Usage: grep -hblcnsviw pattern file . . .


Here's my box info:

ROOT@arivrc: uname -a
SunOS arivrc 5.6 Generic_105181-35 sun4u sparc SUNW,UltraSPARC-IIi-Engine

Assuming that the keyword in the second line is also fixed as is the one in the first line

/usr/xpg4/bin/grep -e <keyword1> -e <keyword2> <filename>

For your file, Let's say
/usr/xpg4/bin/grep -e 91030 -e Answered logxx

That did not work either. Let me see if I can be a little more specific.

Let's say I want to grep xx from logyy. I want not only the instance of xx to return, but the line directly below it as well (no matter what it is).

So basically, I am telling the shell..."find xx in my log yy. Every time you find it, show it to me, and while your at it, give me the line below it as well".

Does that make more sense??

-cd