I am using the code below modified from a post I saw here regarding having the script write out future dates. The problem is that instead of making 8/1 it makes 7/32! Please help!

yy=`date +%Y`
mm=`date +%m`
dd=`date +%d`

echo "Today is : $yy $mm $dd"


#!/usr/bin/ksh

date '+%m %d %Y' | 
{ 
read m d Y
d=`expr "$d" + 1` 
case "$d" in 
        0) 
           m=`expr "$m" + 1` 
                case "$m" in 
                        0) 
                           m=12 
                           Y=`expr "$Y" + 1` 
                        ;; 
                esac 
        d=`cal $m $Y | grep . | fmt +1 | tail +1` 
esac 

echo "Tomorrow is : $m $d $Y" 



d=`expr "$d" + 1` 
case "$d" in 
        0) 
           M=`expr "$m" + 1` 
                case "$m" in 
                        0) 
                           m=12 
                           Y=`expr "$Y" + 1` 
                        ;; 
                esac 
        d=`cal $m $Y | grep . | fmt +1 | tail +1` 
esac 

echo "The day after tomorrow is : $Y$m$d"



d=`expr "$d" + 1` 
case "$d" in 
        0) 
           M=`expr "$m" + 1` 
                case "$m" in 
                        0) 
                           m=12 
                           Y=`expr "$Y" + 1` 
                        ;; 
                esac 
        d=`cal $m $Y | grep . | fmt +1 | tail +1` 
esac 

echo "Two days from today is : $Y$m$d"


}
exit

The code is clearly a bad adaptation of a clever script to calculate yesterday's date.
It basically it would work for yesterday's date with:

d=`expr "$d" - 1`
m=`expr "$m" - 1` 
Y=`expr "$Y" - 1`

d=`expr "$d" + 1`
m=`expr "$m" + 1` 
Y=`expr "$Y" + 1`

Ok. How exactly would I do that? I am using a C shell. Is there a way to read tomorrows date or have it print on the screen with perhaps the cal function? I could possibly use the cut command print the day. If not, how would I "change the logic to suite future dates?"

---------- Post updated at 07:44 AM ---------- Previous update was at 07:42 AM ----------

I am actually running a program that runs out 60 hours so I would need to be able to write the dates for as long as 2 days after tomorrow.

---------- Post updated at 08:34 AM ---------- Previous update was at 07:44 AM ----------

Would it be possible to use the +1 with a -j command to get the number of the day of year then convert the modified julian date back into the standard date?

---------- Post updated at 09:21 AM ---------- Previous update was at 08:34 AM ----------

Ok I found a pretty simple way to do it but I still need to have the month written numerically. How could I do it in conjuction with this command?

date -d "+2 day"

date -d "+3 day" +%y%m%d

I'm sure that in your next post you will mention what Operating System you have and what Shell you are using.
The script posted in post #1 was clearly not "C shell".
The extended "date" functions are not available in standard unix, so we guess that you are running some sort of Linux.

Looks like the Korn shell


---------- Post updated at 01:06 PM ---------- Previous update was at 12:45 PM ----------

If on Linux, ksh is probably actually ksh93. In that case you can do

$ printf "%T\n"  today
Mon Aug  2 00:00:00 EDT 2010
$ printf "%T\n"  "today + 1 day"
Tue Aug  3 00:00:00 EDT 2010
$ printf "%T\n"  "today + 2 day"
Wed Aug  4 00:00:00 EDT 2010
$

I am running on a Linux Box.

[rhuff@huina working]$ echo $SHELL
/bin/csh

---------- Post updated at 12:01 PM ---------- Previous update was at 11:56 AM ----------

My script worked for the date. the kshell script was partially borrowed script from an earlier project which I have had to modify. The line

#!/usr/bin/ksh