![]() |
Hello and Welcome from United States to the UNIX and Linux Forums! Thank You for Visiting and Joining Our Global Community.
|
|
google unix.com
|
|||||||
| Forums | Register | Forum Rules | Links | Albums | FAQ | Members List | Calendar | Search | Today's Posts | Mark Forums Read |
| Shell Programming and Scripting Post questions about KSH, CSH, SH, BASH, PERL, PHP, SED, AWK and OTHER shell scripts and shell scripting languages here. |
More UNIX and Linux Forum Topics You Might Find Helpful
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| Symbol referencing error | fromatz | High Level Programming | 1 | 03-17-2008 06:01 PM |
| symbol referencing error | suhasini | High Level Programming | 1 | 04-03-2006 06:43 AM |
| Referencing variables in commands | mharley | Shell Programming and Scripting | 3 | 03-31-2005 01:37 AM |
| ld: fatal: Symbol referencing errors | alfabetman | UNIX for Dummies Questions & Answers | 2 | 01-08-2002 04:57 AM |
| Compiling Errors -- Symbol referencing | spotanddot | High Level Programming | 5 | 07-11-2001 01:18 PM |
|
|
LinkBack | Thread Tools | Search this Thread | Rate Thread | Display Modes |
|
||||
|
Referencing a range of parameters?
I can't seem to find anywhere how to syntactically reference a range of parameters in the script I am trying to write.
My script requires at least 2 parameters to run, with parameter 1 being the main file, which I want appended to x amount of target files, which will be parameters 2 through whatever. I know how to reference parameters separately like $1, $2, etc., and how to reference all parameters like $#, but how can I reference all parameters except for parameter 1? Example: For all parameters except $1 do if [ ! -rw $?] then; echo "Permission denied!" exit fi done |
| Bookmarks |
| Thread Tools | Search this Thread |
| Display Modes | Rate This Thread |
|
|