Hello,

I will count words in a file (or more files) and count (if given up) empty files (test -z?), how can I do this? Like this:
There are "108" words in "3" files
There are "2" empty files

Thanks for your reaction.

Regards,

Arjan Engbers

(My English is not good, I hope you understand me)

Hi, arjanengbers:

To count the number of words in each file in the current directory (including empty files):

wc -w *

find ~ -empty -type f | wc -l

for i in $@
do
        if [ ! -s $i ]
        then
                echo "$i is empty";
        fi
    echo `wc -w $i`;
done

try the following ,it will give you the exact output,

j=0
k=0
count=0
total=0
for i in $@
do
        if [ -s $i ]
        then
                count=`wc -w $i|cut -d ' ' -f 1`
                let total=$count+$total
                let k=$k+1
        else
                let j=$j+1
        fi
done
echo "There are \"$total\" words in $k files"
echo "There are \"$j\" empty files"