Hi,

i got stuck in creating a search job.

I have a text file which looks like this:

======================
Backup - OK -
Backup - OK -
Backup - ERROR -
Backup - WARNING -
======================

if [ "$(cat database.txt)" = "ERROR" ];
then    
 echo "Found an ERROR."
elif [ "$(cat database.txt)" = "WARNING" ];
then
 echo "Found a WARNING".
else
 echo "Backup sucessful."
fi

You can use the following way.
consider that the file is having the content as follows

cat file
ERROR
hai
this is test
WARNING

while read line
do
if [ "$line" == "ERROR" -o "$line" == "WARNING" ]
then
        echo "Matched line is $line"
fi
done < file

grep 'ERROR' file

The problem with this is that you are asking if "cat database.txt" is exactly "ERROR", which of course it isn't. For tasks like yours, where you want to know if a text contains a certain string there is a Unix command named "grep". Have a look at the man page for grep to find out what you could do with it (which is quite a lot, i can assure you).

Your code should look like:

if [ $(grep -c "ERROR" database.txt) = 0 ]; then
     print - "no error found"
else
     print - "error found"
fi

Try this,

result=`grep -w "ERROR" database.txt`
err=$?
result=`grep -w "WARNING" database.txt`
war=$?
if [ $err -eq 0 ]
then
 echo "Found an ERROR."
elif [ $war -eq 0 ]
then
 echo "Found a WARNING".
else
 echo "Backup sucessful."
fi

You can use the following code

while read line
do

`echo $line | grep "ERROR" >/dev/null`
if [  $? -eq  0 ];
then
        echo "Matched ERROR the line is $line"
fi
done < file

Hey guys,

thanks a lot for the help.

I will try with method works best in my situation.

From now, I will use code boxes for my code. :-)

greetz
lnino

---------- Post updated at 10:19 AM ---------- Previous update was at 08:20 AM ----------

Hi.

I have now implemented the code.
I used the code of bakunin.

I am interested in another feature.

Is it possible to count how often the word ERROR has been found in the text file?

Thanks a lot

greetz
lnino