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#1
03-10-2010
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Remove if the above line matches pattern
but keep if does not I have a file: --> my.out Code:
foo: bar foo: moo blarg i am on vacation foo: goose foo: lucy foo: moose foo: stucky groover@monkey.org foo: bozo grimace@gonzo.net dear sir - blargo blargo foo: goon foo: sloppy foo: saudi gimme gimme gimme i have something for you foo: mad foo: happy foo: foo I want: Code:
blarg i am on vacation foo: goose groover@monkey.org foo: bozo grimace@gonzo.net dear sir - blargo blargo foo: goon gimme gimme gimme i have something for you foo: mad Perhaps, if foo: xxx is not above, keep foo: xxx and any other lines not containing foo: ? Can sed help me? I tried this: Code:
sed '/foo: /{
N
/.*/D
}' my.outbut it didn't totally do it ... Thanks for any help! Last edited by scottn; 03-10-2010 at 04:29 PM.. Reason: Please use code tags |
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#2
03-10-2010
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Hi, spacegoose: Code:
$ cat data foo: bar foo: moo blarg i am on vacation foo: goose foo: lucy foo: moose foo: stucky groover@monkey.org foo: bozo grimace@gonzo.net dear sir - blargo blargo foo: goon foo: sloppy foo: saudi gimme gimme gimme i have something for you foo: mad foo: happy foo: foo Using SED: Code:
$ cat spacegoose.sed
#n
/^foo:/!{
:top
p
/^foo:/!{
n
b top
}
}
$ sed -f spacegoose.sed data
blarg
i am on vacation
foo: goose
groover@monkey.org
foo: bozo
grimace@gonzo.net
dear sir - blargo blargo
foo: goon
gimme gimme gimme
i have something for you
foo: madIf you require a blank line after each sequence: Code:
$ cat spacegooseLF.sed
#n
/^foo:/!{
:top
p
/^foo:/!{
n
b top
}
s/.*//p
}
$ sed -f spacegooseLF.sed data
blarg
i am on vacation
foo: goose
groover@monkey.org
foo: bozo
grimace@gonzo.net
dear sir - blargo blargo
foo: goon
gimme gimme gimme
i have something for you
foo: madUsing AWK: Code:
awk '!/^foo:/,/^foo/' If you require a blank line after each sequence: Code:
awk '!/^foo:/,/^foo/{print; if(/^foo/)print ""}'Cheers, Alister Last edited by alister; 03-10-2010 at 04:11 PM.. |
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#3
03-10-2010
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Thanks Alister, The first example works (thanks  , but the second one yields:Code:
awk: syntax error near line 1 awk: illegal statement near line 1 I'm using Solaris. Last edited by scottn; 03-10-2010 at 04:30 PM.. Reason: Code tags |
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#4
03-10-2010
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Hi.
On Solaris, use /usr/xpg4/bin/awk, or nawk |
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