hi,

is it possible to find the number of occurences of a pattern between two paranthesis.

for e.g

i have a file as below.

>>{
>>hi 
>>GoodMorning
>>how are you?
>>}
>>is it good, 
>>tell me yes, if it is good

awk '/{/,/}/ {if (tolower($0) ~ /good/) {z++}} END{print z}' z=0 infile

Hi,

Im getting this error, when running the command given.
Error msg for rour reference.

awk: There is a regular expression error.
?, *, or + not preceded by valid regular expression

Thanks

how about:

sed -n -e '/{/,/}/ {/good/I p}' file.txt

#!/bin/bash
read -p "Search pattern: " PAT
while true
L=""
do    
    until [ "$L" = "{" ]
    do 
        read L || exit
    done
    until [ "$L" = "}" ]
    do 
        read L || exit
        if $(echo $L | grep -q $PAT)
        then
        ...............
        fi
    done
done

#!/bin/bash
shopt -s nocasematch
while read -r line
do
    case "$line" in
       *{* ) flag=1;count=0;;
       *}* ) flag=0
        echo "count: $count"
       ;;
    esac
    if [ "$flag" -eq 1 ];then
            set -- $line
            for c in $@
            do
                case "$c" in
                    *good* )
                    count=$((count+1))
                esac
            done
    fi
done <"file"

Hi,

Thanks for the response,
what i need is
I have a file like this

------------------------------------
{##############
things are making me bad
bad things are good
thanks for your help
##############}
bad things make me worse
wore things are bad
bad is always good
good is not bad
-------------------------------

I need to count bad not in between {}
ie count = 4

It will be very helpful for me