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12-01-2009
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Trying to improve radoulov solution  Code:
# cat /etc/group
hostname Groupname GID Userlist Date
myHot operaors 54 542 542 542 542 542 542 542 user1 user9 24/11/2009
myHost operators 542 542 542 542 542 542 542 542 user2 24/11/2009
myHost operators 542 542 542 542 542 542 542 542 user3 24/11/2009
myHost operators 542 542 542 542 542 542 542 542 user4 24/11/2009
myHost operators 542 542 542 542 542 542 542 542 user5 24/11/2009
myHost operators 542 542 542 542 542 542 542 542 user6 user7 24/11/2009
# awk -F'\t' 'NR>1{split($3, g, " ");n=split($4,u," ");for(i=0;++i<=n;){print $1,$2,g[1],u[i],$NF}next}1' OFS=\\t /etc/group
hostname Groupname GID Userlist Date
myHot operaors 54 user1 24/11/2009
myHot operaors 54 user9 24/11/2009
myHost operators 542 user2 24/11/2009
myHost operators 542 user3 24/11/2009
myHost operators 542 user4 24/11/2009
myHost operators 542 user5 24/11/2009
myHost operators 542 user6 24/11/2009
myHost operators 542 user7 24/11/2009
OP whould watch for Useless Use of Cat Award
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12-02-2009
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i'll reframe my problem...this should be easy to debug ... Code:
bash-3.00$ A=`cat /etc/group|awk -F: '{if ($1$3 == "secur138"){print $NF}}'|sort|uniq`
bash-3.00$ echo $A
t9330sp,t0096pg,t6899bs,t2483eb,t1563dr,t6658pb t9330sp,t0096pg,t6899bs,t2483eb,t1563dr,t6658pb,smadmn,sysweb,root
See that green colored string....rest all strings(or members) are comma separated....whereas this string is not..it should have been t6658pb,t9330sp... and its happening because Code:
bash-3.00$ cat /etc/group|awk -F: '{if ($1$3 == "secur138"){print $NF}}'
t9330sp,t0096pg,t6899bs,t2483eb,t1563dr,t6658pb
t9330sp,t0096pg,t6899bs,t2483eb,t1563dr,t6658pb,smadmn,sysweb,root
i have two groups defined with same name and id ,but few diffrent members.... My code looks like following to capture these comma separated strings: Code:
Host etcGroup DUP:
cat /etc/group | awk -F':' '{print $1$3}'|sort|uniq
Userlist:
A=`cat /etc/group|awk -F: '{if ($1$3 == "@@Host etcGroup.DUP@@") {print $NF}}'|sort|uniq`
B=`echo $A|wc -w`
if [ $B = 0 ]
then
echo NULL
else
count=`echo $A| nawk -F, {'print NF'}`
i=1
while [ $i -le $count ]
do
str[$i]=`echo $A| cut -d, -f${i}`
echo "${str[$i]}"
i=`expr $i + 1`
done
fi
any ideas? Regards Abhi |
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12-03-2009
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To anwer your query: Quote:
Code:
group:x:1024:member1,member2,member3 groupa:x:1024:member4,member5,member6 groupb:x:1024:member7,member8,member9 If the have the same name then in Solaris only one of the lines would count, proof would be to run: Code:
$ getent group <groupname> To query the group that has two lines with the same name and GID using an OS call and see what gets listed. |
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