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11-30-2009
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Obtaining day before a given date
Hi all,
is there a way using GNU (Solaris 8) methods of obtaining the day before a given day? i.e. 2007-09-09.... I would like the date a day before it so output would be 2007-09-08. Format YYYY-MM-DD I know I can subtract the day number using cut and expr but it would get tricky if the date was 2007-09-01 for example and would also make my script long with all the permutations of checking months, years etc. |
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11-30-2009
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Quote:
I get the following: date: illegal option -- d usage: date [-u] mmddHHMM[[cc]yy][.SS] date [-u] [+format] date -a [-]sss[.fff] |
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11-30-2009
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-d (or --date) is an option that is specific to the GNU version of date.
Seems that you don't use GNU commands. In that case, consult the post Yesterdays Date/Date Arithmetic Jean-Pierre. |
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