help with sed command

tranz435 · #1 (**permalink**) 11-02-2009

Hi,

I am new to Unix scripting. I have a list as shown below. Now, I want to list only those words that doesnt start with "-".

PGM_LIST=" \
cls/dw_realease1 \
cls/dw_realease2 \
-cls/dw_realease3 \
cls/dw_realease4 \
-cls/dw_realease5 \
cls/dw_realease6 \
"

I tried this:
echo $PGM_LIST | sed '/-/d'

but its not giving correct results. Please help! I am using ksh

scottn · #2 (**permalink**) 11-02-2009

Why would you do that?

The shell interprets \ as a continuation character, not a newline. The newline that follows \ is removed.

tranz435 · #3 (**permalink**) 11-02-2009

Yes, you are right, but I need to list all the words which doesnt start with "-"

So I want to see the output as:

cls/dw_realease1 cls/dw_realease2 cls/dw_realease4 cls/dw_realease6

basically omitting cls/dw_realease3 and cls/dw_realease5

scottn · #4 (**permalink**) 11-02-2009

Code:

echo $(echo $PGM_LIST | awk -v RS=" " '!/-/')

tranz435 · #5 (**permalink**) 11-02-2009

thanks! this is all I needed. Thanks for your help!

svenkatareddy · #6 (**permalink**) 11-02-2009

grep -v '^-'

Scrutinizer · #7 (**permalink**) 11-02-2009

Code:

echo $PGM_LIST|sed 's/-[^ ]* //g'

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