My input:
>seq_1
DSASSTRRARRRRTPRTPSLRSRRSDVTCS
>seq_3
RMRLRRWRKSCSERS*RRSN
>seq_8
RTTGLSERPRLPTTASRSISSRWTR
>seq_10
NELPLEKGSLDSISIE
>seq_9
PNQGDAREPQAHLPRRQGPRDRPLQAYA+
QVQHRRHDHSRTQH*LCRRRQREDCDRLHR
>seq_4
DRGKGQAGCRRPQEGEALVRRCS>seq_6
FA*GLAAQDGEA*SGRG

My output: Extract all the data after seq_3:
>seq_8
RTTGLSERPRLPTTASRSISSRWTR
>seq_10
NELPLEKGSLDSISIE
>seq_9
PNQGDAREPQAHLPRRQGPRDRPLQAYA+
QVQHRRHDHSRTQH*LCRRRQREDCDRLHR
>seq_4
DRGKGQAGCRRPQEGEALVRRCS>seq_6
FA*GLAAQDGEA*SGRG

Does anybody got the idea to get my desired output?
It seems like awk and sed able to do it.
But I not very sure how to solve it out.
Thanks a lot for all of your advice

you had previous posts similar to this. so i expect you to already have some code. show it.

code

sed -n '/seq_8/,$ {
p
} 'file.txt > out_file

Thanks a lot, it is worked perfectly

Hi,
I just found out that the code that you suggested also will print out the content of seq_81,seq_800,etc
Do you have any idea just only specific and only print out the content that matched with seq_8?
Thanks a lot ^^

easily you can put ur string inside this "\<\>" and you will get the exact pattern you want.

sed -n '/\<seq_8\>/,$ {
p
} ' file.txt > out_file

above you will get seq_8 only if you want seq_80 do this:
sed -n '/\<seq_80\>/,$ {
p
} ' file.txt > out_file

and so on.

hi,
I just try both of the code that you suggested, it print out all the content of the file
I not sure what is the wrong that I had did
Do you know what is the reason?
Thanks again, ahmad