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10-23-2009
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Display LineNo Incase Total Number Of Delimiter Does Not Not matches in a given variable
I have many files .dat extension.
requirement is to display line no if no of delimiter does not matches in a given variable lets say File: REF_BETOS.dat HCPCS_OR_CPT_CODE~BETOS_CODE~TERMINATION_DATE 0001F~Z2~ 0003T~I4~B20061231 0005F~Z2~~~ 0008T~P8~B20061231 0008T~P8~B20061231~feess 00100~P0~ Delimiter=2 Output should display the filename and lineno your help is appreciated I am trying with statment awk -F"$Delimiter" '{print NR NF-1}'; OutPut should look like File Name Line No REF_BETOS.dat 4 REF_BETOS.dat 6 Last edited by ainuddin; 10-23-2009 at 11:29 AM.. Reason: Thread tital should be "Delimiter Does Not matches" |
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