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08-27-2009
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Run multiple commands in $() without opening a new shell
The code below works, but takes too many lines and looks awkward: Code:
db2 "export to $filename of del select * from $table with ur"|tee -a $LOGFILE|awk '/Number of rows exported:/ {print $5}' > numrows.tmp
numrows=$(cat numrows.tmp)
rm numrows.tmp
When I try the statement below instead, I get a message saying there's no connection to the database. That's because it opened a new shell. It's opening a new shell when I give more than just the db2 command. How can I get the code below work: Code:
numrows=$(db2 "export to $filename of del select * from $table with ur"|tee -a $LOGFILE|awk '/Number of rows exported:/ {print $5}' )
Thanks in advance Naveen Last edited by Franklin52; 08-27-2009 at 04:42 PM.. Reason: Please use code tags! |
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08-27-2009
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You can read the value like this: Code:
db2 "export to $filename of del select * from $table with ur"|tee -a $LOGFILE|awk '/Number of rows exported:/ {print $5}' | read numrows
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08-27-2009
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numrows variable is not getting anything assigned by read.
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