grep '\~' b | awk '{print $1","$3}' | sed -e 's/~//g'

harshakusam · #1 (**permalink**) 08-25-2009

Hi all,

Code:

   
grep '\~' b | awk '{print $1","$3}' | sed -e 's/~//g'

Iam using above command for some report...

can this be done using any one of them either sed or awk or grep...

rakeshawasthi · #2 (**permalink**) 08-25-2009

Try:

Code:

awk '/~/ {$1=sub(/~/,"",$1); $3=sub(/~/,"",$3); print $1","$3}' b

harshakusam · #3 (**permalink**) 08-25-2009

$ nawk '/~/ {$1=sub(/~/,"",$1); $3=sub(/~/,"",$3); print $1","$3}' b
1,0
1,0
1,0
1,0
1,0
1,0
1,0
1,0
1,0
1,0
1,0

Iam getting above output

rakeshawasthi · #4 (**permalink**) 08-25-2009

Sorry did not get your req correct...
Try:

Code:

awk '/~/ {gsub(/~/,"",$1); gsub(/~/,"",$3); print $1","$3}' b

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