How to get it's own file name within the same shell script?


 
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# 1  
Old 10-23-2003
How to get it's own file name within the same shell script?

Hello all,

This may be a silly question, but, let me ask... I searched the knowledge base, but couldn't get any help...

My script creates a log file. I need to name log file as whatever the script name with a ".log" extension.

Example: For the script name "start_cmd.sh", the log file should be named "start_cmd.sh.log" in the same script directory.

How do I get the script file name within the shell script?

Thanks.
# 2  
Old 10-23-2003
It should be in $0. (that is dollar zero)
# 3  
Old 10-24-2003
Thanks for the help Perderabo.
# 4  
Old 10-28-2003
Belt and braces...

To be sure that you only get the script name, try using:

basename $0

Like so:

LogFile="$(basename $0).log"

This solves the issue of calling the script with a path name attached to the front.
This User Gave Thanks to Simerian For This Post:
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