Hello, I'm having a problem figuring out the syntax for padding 10-99. Everything else in the program works fine so I want to focus in on just this part of the code. Below is a snippet of the code that I am having problems with. I appreciate all the help I can get. Thank you.

The script basically takes an image and adds the convert charcoal filter and spits out a sequence the user specifies. Problem is if the frame goes over 100...the padding is thrown off since 100 is set for greater than or equal to, where 10-99 needs to be specified to a limit before 100.

I seen a for loop where it prints like so..

for i in {10..99} etc... but that will not work, it only prints and {10..99} does not work for an if statement.


##no problem here

if [ $count -lt 10 ]; then
convert ${IMGDIR}${IMG} -charcoal $count ${OUTDIR}${OUT}.000$count.jpg
fi


##cant figure out the arithmatic here!

if ( $count -ge 10 > 99 ); then
convert ${IMGDIR}${IMG} -charcoal $count ${OUTDIR}${OUT}.00$count.jpg
fi


##no problems here.

if [ $count -ge 100 ] ; then
convert ${IMGDIR}${IMG} -charcoal $count ${OUTDIR}${OUT}.0$count.jpg
fi

$
$ count=10
$ echo $count
10
$
$ while [ $count -le 20 ] ; do
>   echo $count
>   count=`expr $count + 1`
> done
10
11
12
13
14
15
16
17
18
19
20
$

Can there be a while loop inside of a while loop? I already had one at the top. Heres the code edited. It's not correct, please correct me where im wrong.

count=$START
while [ $count -le $END ];
do
echo $count

if [ $count -lt 10 ]; then
convert ${IMGDIR}${IMG} -charcoal $count ${OUTDIR}${OUT}.000$count.jpg
fi

count=10
while [ $count -le 99 ]; do
convert ${IMGDIR}${IMG} -charcoal $count ${OUTDIR}${OUT}.00$count.jpg
count=`expr $count + 1`
done


if [ $count -ge 100 ] ; then
convert ${IMGDIR}${IMG} -charcoal $count ${OUTDIR}${OUT}.0$count.jpg
fi


SETTING=$(echo "scale=4; 1/50" | bc)
echo "processing frame: "$count""

let count=count+1

done

So are those IF conditions inside the loop simply to ensure that the width of the number between ${OUT} and ".jpg" is constant ?

If so, then you could use "printf" and avoid those IF conditions -

$ 
$ OUT=myimage
$ count=1
$ 
$ while [ $count -le 100 ]; do
>   x=`printf "%s.%04d.jpg" $OUT $count`  # this is your output file, fixed width
>   echo $x                               # run your commands; "convert" etc.
>   count=`expr $count + 1`               # increment count
> done
myimage.0001.jpg
myimage.0002.jpg
myimage.0003.jpg
myimage.0004.jpg
myimage.0005.jpg
myimage.0006.jpg
myimage.0007.jpg
myimage.0008.jpg
myimage.0009.jpg
myimage.0010.jpg
myimage.0011.jpg
myimage.0012.jpg
...
... <output snipped for brevity>
...
myimage.0098.jpg
myimage.0099.jpg
myimage.0100.jpg
$ 
$

You can't do this because you reset count to 10 everytime. That won't get anything over 100 if count goes over 100.

count=10
while [ $count -le 99 ]; do
convert ${IMGDIR}${IMG} -charcoal $count ${OUTDIR}${OUT}.00$count.jpg
count=`expr $count + 1`
done

if [ $count -ge 10 && $count -le 99 ]
convert ${IMGDIR}${IMG} -charcoal $count ${OUTDIR}${OUT}.00$count.jpg
fi

Hmm..when I run this...

if [ $count -ge 10 && $count -le 99 ]; then
convert ${IMGDIR}${IMG} -charcoal $count ${OUTDIR}${OUT}.00$count.jpg
fi

line 88: [: missing `]'

Sorry,
That shoudl be

if [ $count -ge 10 ] && [ $count -le 99 ] ;then