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07-20-2009
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AWK Utitlity
Hi All,
Greetings for the day. I request your thoughts on the below. I have replace one particular substring in a string.I could get the substring value using awk command. echo | awk '{ print substr("'"${String}"'",3,4) }'. I need to replace this with a new value in the same string. Please throw some light on this. Thanks, RSC1985 |
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07-20-2009
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try.. Code:
-bash-3.2$ echo $String
abcdefg
-bash-3.2$ echo ${String/cdefg/CDEFG}
abCDEFG
-bash-3.2$
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07-20-2009
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Quote:
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07-20-2009
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You may want to consider Perl. String manipulation in Perl is amazingly flexible. Quote:
Code:
$ $ echo $x abcdefg $ $ echo $x | perl -ne 's/defg/DEFG/; print' abcDEFG $ Quote:
Code:
$
$ # Original string => "abcdefg abcdefg abcdefg"
$ # Transformed string => "abcdefg abcUVWXYZ abcdefg"
$
$ echo $y
abcdefg abcdefg abcdefg
$
$ echo $y | perl -ne '$c=0; s{(abc)(defg)}{if (++$c==2){ $1."UVWXYZ" }else{ $1.$2 }}gex; print'
abcdefg abcUVWXYZ abcdefg
$
HTH, tyler_durden ---------- Post updated at 11:49 AM ---------- Previous update was at 11:40 AM ---------- The code posted above was the solution of the problem: "In the string S, replace inline the Nth occurrence of substring X to Y". If the problem is: "In the string S, replace inline to X, the substring of length M starting at position N", then that is simpler in Perl. Code:
$ $ echo $y abcdefg abcdefg abcdefg $ $ # Replace the substring of 4 characters, starting at position 11, to "UVWXYZ" $ $ echo $y | perl -ne 'substr($_,11,4)="UVWXYZ"; print' abcdefg abcUVWXYZ abcdefg $ tyler_durden |
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07-20-2009
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If you have not veryveryold ksh then string manipulation is like posix says. (Posix has used ksh93 ...). So you can use bash, ksh93, ... If you use some commercial unix, usually they have many ksh version in different location: Code:
find / -name ksh How to test have you ksh93/posix compatible shell ? Ex. take two first letters from your LOGNAME variable: Code:
substr=${LOGNAME:0:2}
echo "$substr"
Code:
# take first two letters then something new next 4 letters and rest of str is still old
newstr="${str:0:2}NEW${str:6}"
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