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Old 07-16-2009
donisback donisback is offline
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Join Date: May 2009
Posts: 9
Use awk to have the fourth column with spaces

Hi Gurus,
We have a ftpserver from which we do a dir command and output it to a local file.
The content of the ftpfile is:

Code:
07-15-09  06:06AM                 5466 ABC_123_ER19057320090714082723.ZIP
07-15-09  06:07AM                 3801 ABC_123_ER19155920090714082842.ZIP
07-15-09  06:07AM                 2034 ABC_123_ER19257020090714083003.ZIP
07-15-09  06:07AM                 5346 ABC_123_ER19456120090714083105.ZIP
07-15-09  06:07AM                50188 ABC_123 4507131004299717363.ZIP
07-15-09  06:07AM                10867 ABC_69 ER194561.ZIP
07-15-09  06:07AM                73183 ABC_69_ER194631.ZIP
07-15-09  06:07AM                 1576 ABC_69_ER195427.ZIP
07-15-09  06:07AM                 5880 ABC_69_ER195428.ZIP

I generally use awk '{print $4}' ftpfile. But, I realized that the filename in the ftp might contain spaces.
So I came up with the command:

Code:
awk '{i=4;while (NF>=i) {print $i;i++}}' ftplist

But the above command prints new line for every print I give. I want it in the same line. I tried using cut but it doesn't help.
On an ad-hoc basis, I am currently using the below command:
awk '{if (NF!=4) {print $4,$NF}else {print $4}}' ftplist
The above command prints what I want but, I assume here that the filename will have only one space.
Please suggest.
 

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