|
|
|
google unix.com
|
|||||||
| Forums | Register | Forum Rules | Links | Albums | FAQ | Members List | Calendar | Search | Today's Posts | Mark Forums Read |
| Shell Programming and Scripting Post questions about KSH, CSH, SH, BASH, PERL, PHP, SED, AWK and OTHER shell scripts and shell scripting languages here. |
More UNIX and Linux Forum Topics You Might Find Helpful
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| unable to access a variable not local to a while loop | codeman007 | Shell Programming and Scripting | 6 | 12-25-2008 04:56 PM |
| running command remotely to populate local variable | hcclnoodles | Shell Programming and Scripting | 3 | 11-20-2008 11:02 AM |
| bash and ksh: variable lost in loop in bash? | estienne | Shell Programming and Scripting | 2 | 08-25-2008 03:09 PM |
| passing variable from bash to perl from bash script | arsidh | Shell Programming and Scripting | 10 | 06-04-2008 01:25 PM |
| Global variable becomes local | odashe318 | Shell Programming and Scripting | 2 | 10-29-2004 10:18 PM |
Powered by 
|
|
|
LinkBack | Thread Tools | Search this Thread | Rate Thread | Display Modes |
07-03-2009
|
||||
|
||||
|
new local variable in bash
hi,
i need to add a new local variable to my script. then i want to display its value along the title(with echo). desired result: password = x Actual result: x for some reason the below line displays the x value. password=cat config.xml |grep 'DB Password'|cut -f3 -d '='|cut -f2 -d '"' why is it that when i run the script it display the new variable & how can i avoid it value? thanks... |
| Bookmarks |
| Thread Tools | Search this Thread |
| Display Modes | Rate This Thread |
|
|
Threaded Mode
