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07-03-2009
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Pulling correct value from Mapfile
Hi all, I am trying to pull one value from a Mapfile, but the result is that I am getting all the values. The Mapfile maps the host name from the Backup Server to the host name in our Network Monitoring Server, as shown here: Mapfile Code:
cat zabbixhosts Helpdesk-fd:Server_Helpdesk Knowledge-fd:Server_Knowledge BaculaServer-fd:Server_Bacula Zabbix-fd:Server_Zabbix_1.4.2 The section of script that is failing is here: Code:
client=$(tail -n 38 /var/lib/bacula/log | grep -m 1 -F "Client" | awk -F" " '{ print $2; }')
echo Client is $client
echo
# get hostname from the Hostsfile
ZABBIX_HOST=`grep "[$client]" $ZABBIX_HOSTSFILE`
if [ $? -eq 0 ]; then
hostname=`echo "$ZABBIX_HOST" | cut -f2 -d:`
else
hostname=""
fi
echo Hostname is $hostname
When I run that script the output is as follows: Code:
./bacula2zabbix.sh Client is "BaculaServer-fd" Hostname is Server_Helpdesk Server_Knowledge Server_Bacula Server_Zabbix_1.4.2 Any advice would be greatly appreciated. Thanks. Last edited by MrKen; 07-03-2009 at 03:16 AM.. Reason: Bad cut n paste |
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07-03-2009
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Did you initialize host file name?
I tried the same code snippet.The result is
Client is "BaculaServer-fd" Hostname is Server_Bacula ZABBIX_HOSTSFILE="path of map file" I made two changes: 1.Initialized ZABBIX_HOSTSFILE to map file name 2.Removed [] grep "[$client]" $ZABBIX_HOSTSFILE grep "$client" $ZABBIX_HOSTSFILE |
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07-03-2009
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Thanks for the quick reply. When you say 'initialize' the host file name, I guess you mean do I have this: ZABBIX_HOSTSFILE="/etc/bacula/zabbixhosts"; Yes, I have that already. That's why there is a result to the output in the first post. When I remove the [ ] as suggested, the output is now: Code:
Client is "BaculaServer-fd" Hostname is Any more ideas? |
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07-03-2009
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Code:
hostname=`grep $client zabbixhosts | cut -f2 -d:` I tried to simulate your scenario in my linux machine. Assuming that your client variable contains <BaculaServer-fd >. From the above code, variable hostname contains Server_Bacula if grep is successfull and will contain no value if it fails. Something like this.... Code:
$ cat zabbixhosts Helpdesk-fd:Server_Helpdesk Knowledge-fd:Server_Knowledge BaculaServer-fd:Server_Bacula Zabbix-fd:Server_Zabbix_1.4.2 $ echo $client sai $ hostname=`grep $client zabbixhosts | cut -f2 -d:` ; echo $hostname $ client="BaculaServer-fd" $ hostname=`grep $client zabbixhosts | cut -f2 -d:` ; echo $hostname Server_Bacula $ hostname=`grep -w $client zabbixhosts | cut -f2 -d:`; echo $hostname Server_Bacula |
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07-03-2009
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reddybs, thanks for your reply. If I change "[$client]" to $client, then I get no hostname output. If I use -w with grep, then I get no hostname output. So now I have this, but still the output is incorrect. Code:
echo Client is $client echo # get hostname from the Hostsfile hostname=`grep "[$client]" $ZABBIX_HOSTSFILE | cut -f2 -d:` ; echo $hostname and the output: Code:
Client is "BaculaServer-fd" Server_Helpdesk Server_Knowledge Server_Bacula Server_Zabbix_1.4.2 Any more ideas? |
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