awk command-logging

pravfraz · #1 (**permalink**) 07-01-2009

hi folks,

In the following code, logfile remains empty.

Code:

 
log_file="/u/Sc/prav.log.$mon$day"
 
ps -ef | grep "myprocess"| awk -v logfile=$log_file '{
 system("date >> logfile")
}'

can u please help as how to log the date to that logfile.
thanks in advance!

rakeshawasthi · #2 (**permalink**) 07-01-2009

For me your code generates a file with the name "logfile" in the current directory and prints the date there.
Are you initialising the variables "mon" and "day" somewhere?

vgersh99 · #3 (**permalink**) 07-01-2009

Quote:

Originally Posted by pravfraz

hi folks,

In the following code, logfile remains empty.

Code:

 
log_file="/u/Sc/prav.log.$mon$day"
 
ps -ef | grep "myprocess"| awk -v logfile=$log_file '{
 system("date >> logfile")
}'

can u please help as how to log the date to that logfile.
thanks in advance!

why do you need awk? Cannot you use file redirection instead?
If you do need awk, why do you need 'grep'? Awk can do it all.
ps -ef | awk -v logfile="${log_file}" '/myprocess/{cmd="date >> " logfile; system(cmd); close(cmd)}"

pravfraz · #4 (**permalink**) 07-02-2009

thanks a lot!!
i resolved it with your help!
forum rocks!!

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