hi

i try to test the last character in a variable (here $i )

assume i=kljlkjlkA it should be KO and lkjljjlT KO

if [ "echo $i|grep A$" ]
then
echo "ending with A"
else
echo "no A at the end"
fi

whether i is ending or not with A i got "no A at the end"

i tried with simple [ double this is the same , i think the pb is with the Interpretation of A$

thanks in advance
Christian

It's not that simple, I daresay - but possible, of course:

#! /bin/bash

INPUT="$1"
LENGTH=${#INPUT}
if [ "${INPUT:$(($LENGTH-1)):1}" = "O" ]
then
  echo "good"
else
  echo "bad"
fi

exit 0

[house@leonov] sh test.bash 'kljlkjlkA it should be KO and lkjljjlT KO'
good

Here are two ways of doing it. Both ways work in bash and ksh93

i=kljlkjlkA

if [[ ${i: -1} == "A" ]]
then
    echo "ending with A"
else
    echo "no A at the end"
fi

if [[ $i =~ A$ ]]
then
    echo "ending with A"
else
    echo "no A at the end"
fi

thanks but it doesn't work for me :

# sh test.bash 'kljlkjlkA it should be KO and lkjljjlT KO'
test.bash[6]: "${INPUT:$(($LENGTH-1)):1}": bad substitution

i'm in ksh but in bash it's the same !

regards
Christian

-----Post Update-----

Thanks to help me :

i=kljlkjlkA

if [[ ${i: -1} == "A" ]]
then
echo "ending with A"
else
echo "no A at the end"
fi

=> i got :

# test.ksh
test.ksh: ${i: -1}: bad substitution

if [[ $i =~ A$ ]]
then
echo "ending with A"
else
echo "no A at the end"
fi

==> i got :
test.ksh
test.ksh: syntax error at line 1 : `=~' unexpected

regards