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05-27-2009
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separate file by line length
hi all,
i'm new in unix.... i have question, sorry if it's missplace or too silly let say i have a file name testfile.log that contains data 000001 000002 000003 aaaaaaaaaaaaaaaaaa bbbbbbbbbbbbbbbbbbbb cccccccccccccc dddddddddddddddddd 000004 i want to make new file (newfile.log) that only consist aaaaaaaaaaaaaaaaaa bbbbbbbbbbbbbbbbbbbb cccccccccccccc dddddddddddddddddd ps: what i want is, i split by line length which is > 6 regards, steven |
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05-27-2009
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Quote:
Code:
$ $ # display contents of testfile.log $ cat testfile.log 000001 000002 000003 aaaaaaaaaaaaaaaaaa bbbbbbbbbbbbbbbbbbbb cccccccccccccc dddddddddddddddddd 000004 $ $ # pick up only those lines that are more than 6 chars long $ awk 'length > 6' testfile.log aaaaaaaaaaaaaaaaaa bbbbbbbbbbbbbbbbbbbb cccccccccccccc dddddddddddddddddd $ $ # pick up only those lines that are more than 6 chars long AND put them in a new file $ awk 'length > 6' testfile.log > newfile.log $ $ # verify that the new file has the stuff you want $ cat newfile.log aaaaaaaaaaaaaaaaaa bbbbbbbbbbbbbbbbbbbb cccccccccccccc dddddddddddddddddd $ $ |
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05-27-2009
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thx
thx help alot
-----Post Update----- another question i want to make new file that dont consist particular string for example "bbbb" i have aaaaaaa vbbbbq abbbbx cccccc ddddd i want to make new file that consist aaaaaaa cccccc ddddd thx before |
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05-27-2009
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you questions are very simple to do. what have you got ? someone has already shown you how to use awk. Look up the awk documentation and see how you can do the second task.
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