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#1
05-12-2009
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grep/egrep end of pattern
Hi I use arp to get the mac-addresses of my hosts. Code:
# arp -a | grep 192.168.0. e1000g0 192.168.0.1 255.255.255.255 o 00:00:00:00:00:01 e1000g0 192.168.0.11 255.255.255.255 o 00:00:00:00:00:02 e1000g0 192.168.0.2 255.255.255.255 00:00:00:00:00:03 e1000g0 192.168.0.22 255.255.255.255 o 00:00:00:00:00:04 e1000g0 192.168.0.3 255.255.255.255 00:00:00:00:00:05 e1000g0 192.168.0.33 255.255.255.255 00:00:00:00:00:06 How can I grep/egrep for just one host? I'd like to have the following: Code:
# arp -a | grep "192.168.0.1" e1000g0 192.168.0.1 255.255.255.255 o 00:00:00:00:00:01 and not Code:
# arp -a | grep "192.168.0.1" e1000g0 192.168.0.1 255.255.255.255 o 00:00:00:00:00:01 e1000g0 192.168.0.11 255.255.255.255 o 00:00:00:00:00:02 |
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#2
05-12-2009
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Try the -w option of grep.
Regards |
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#4
05-12-2009
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you can also try out as
arp -a | grep "192.168.0.1 " |
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#5
05-12-2009
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Quote:
Regards |
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#6
05-12-2009
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Quote:
 But I have an other question: How can I grep/egrep for exactly two (192.168.1 AND 192.168.2 for example) hosts? Code:
arp -a | egrep '192.168.0.(1|2)' This egrep delivers four hosts. Last edited by domi55; 05-12-2009 at 08:27 AM.. |
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#7
05-12-2009
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arp -a | awk '{print $2}' | grep "192.168.0.[1-2]$"
check this out |
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