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05-06-2009
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How to format the output using float in awk{printf}
Hi
I'm using awk to manipulate the data in the 6th field of the file xxx_yyy.hrv. The sample data that is available in this field is given below 220731.7100000000000000 When i tried using this command cat xxx_yyy.hrv | awk '{printf("%23.16f\n",$6*-1)}' I get the output as -220731.7099999999991269 but i need the output as -220731.7100000000000000 Plz let me know on the format that i should be using to retreive the desired output. Thanks!!! |
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05-07-2009
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Hi vgersh99!!!
I tried with command that you've given awk '{printf("%23.16f\n", sprintf("%.2f", $6-1))}' xxx_yyy.hrv | head -5 | tail -1 but i get the output as 220730.7099999999991269 but i need the output to be -220731.7100000000000000 My requirement is to multiply the 6th field value with -1, and my pbm is the value after the decimal point gets modified when it is multiplied. Plz let me know for any other possibilities also. Thanks!!! |
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05-07-2009
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It Worked
 !!! Thanks a lot!!! |
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