hi,

when i am doing the following things getting error
Can anyone please suggest

i have a file where there is a line like the following
branch=dev sdf dev jin kilii fin kale boyle dev james dev

i want to search the existance of dev in the above line.

cat "$file" | sed -n '/'$branch'p' | sed 's/'$name'/&\n/g' | grep $name |wc -l

where
$file=filename
$branch=line containing branch
$name=dev

while i am doing the above result is 1,but it should be 4

Please suggest

Why not use a single sed statement ?

sed -e "s/\(${branch}.*\)${name}/\1\n/g" ${file}

The follwing is the correct sed (syntactically)

cat "$file" | sed -n ''$branch''p'' | sed 's/'$name'/&\n/g' | grep $name |wc -l

don't know whether it will gives you correct OP or not

What exactly you need ?..i mean your requirement.

You posted

where
$file=filename
$branch=line containing branch
$name=dev

but if you pass any numeric value for $brach say 1 or 2. The sed will print tht particular line and again some other searches and replaces. As always ther will be only one line , wc -l will result in 1.

How ever if u want to search for the existence of a word called "dev" in a specific line the following will do the job :

cat "$file" | sed -n ''$branch''p'' |deroff -w | sort | uniq -c  |grep $name | awk '{ print $1} '

Hi Panyam,

Thanks for ur reply.
Can u please give some idea about deroff command.
i have seen its man page but cannt understand .

Please help.

Hi Milan,

In this context of use "deroff -w" , the output is a word list, one ``word'' per line, with all other characters deleted.

I too not that much aware of it's use. From google i found that :

"Deroff reads each file in sequence and removes all nroff and troff(1) requests and non–text arguments, backslash constructions, and constructs of preprocessors such as eqn(1), pic(1), and tbl(1). Remaining text is written on the standard output"

If you are interested u can go through the link to find more about nroff and troff:

Ch 8 -- Basic Formatting with troff/nroff

Hi Panyam,

Actally the line is of the form as given below
branch=dev:sdf:dev:jin:kilii:fin:kale:boyle:dev:james:dev

i have set IFS=:
then execute

cat "$file" | sed -n ''$branch''p'' |deroff -w | sort | uniq -c |grep $name | awk '{ print $1} '

but it is not giving no fo dev present.
Plese reply

Dear Milan ,

It's working Fine for me.

TEST>cat file
branch=dev:sdf:dev:jin:kilii:fin:kale:boyle:dev:james:dev

TEST>IFS=:

TEST>cat "$file" | sed -n ''$branch''p'' | deroff -w
branch
dev
sdf
dev
jin
kilii
fin
kale
boyle
dev
james
dev
TEST>cat "$file" | sed -n ''$branch''p'' | deroff -w | sort |uniq -c |grep $name | awk '{print $1>
4

Chk it once again the branch and name values your passing.