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04-23-2009
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row to column
Hi
I have a file that contains blocks of data. Each block contains 3 rows of data. The block starts with a string <--- ending is <----- <--- A B C D E F <--- I want to dump this block in a separate file in the format A B C D E F A B C D E F |
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04-23-2009
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Code:
awk '{ if ($0 ~ "^<" ) { print "" }
else { printf("%s ", $0) } }
END { print "" } ' filename > newfilename
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