reading in arguments with spaces - Page 2

Calypso · #1 (**permalink**) 04-23-2009

Yes I am using the while loop for other purpases

Im afraid its still not working, if i type in "5 * 5" and then print out all array elements i get

element 0 - "5"
element 1 - "file 1 in directory"
element 2 - "file 2 in directory"
element n-1 - "file n in directory"
element n - "5"

Calypso

lavascript · #2 (**permalink**) 04-23-2009

Right i see.

So you need to store anything including any character in an array or do you want to throw away anything other than say digits or numbers?

What you need to start doing is checking the contents of $element before assigning it.

What is a fuller scope of what you're trying to do then i may be able to help further

Calypso · #3 (**permalink**) 04-23-2009

making a basic calulator e.g similiar to bc
5 + 5
=10
5 * 5
=25
4 - 2
=2
quit

Curretly my script works for everything except "5 * 5"

Calypso

rwuerth · #4 (**permalink**) 04-23-2009

The following does work in bash in cygwin (the only place I have a bash shell to test)
and it's the same code as CFA Johnson's, except I'm printing the [1] element as that is the "*" which seems to be giving you problems. I'm not getting any problems this way.

Code:

read input
set -f
oldIFS="$IFS"
IFS=' '           # space
array=( $input )
echo ${array[1]}
IFS="$oldIFS"

results:

Code:

./test.sh          # invoke script
5 * 5               # user input
*                    # output of the echo command

Calypso · #5 (**permalink**) 04-23-2009

Thanks rwuerth

that sorted out the problem

Calypso

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