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ls command format display
Hi I have 3 files
[osbadmin@qa1 cp]$ ls -l -rw-r--r-- 1 osbadmin osbadmin 427701 Apr 22 12:06 SANITY_TEST -rw-r--r-- 1 osbadmin osbadmin 427701 Apr 22 12:06 Success 123333 -rw-r--r-- 1 osbadmin osbadmin 427701 Apr 22 12:06 Success 123333 (1) I need to see this "SANITY_TEST" "Success 123333" "Success 123333 (1)" that means I have to use this as array elements as arr=("SANITY_TEST" "Success 123333" "Success 123333 (1)") Please help me. Thanks in advance |
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it's not working plz hlp
Quote:
Hi When I tried this command on [osbadmin@qa1 cp]$ ll total 1272 -rw-rw-r-- 1 osbadmin osbadmin 0 Apr 22 14:38 a b -rw-r--r-- 1 osbadmin osbadmin 427701 Apr 22 12:06 SANITY_TEST -rw-r--r-- 1 osbadmin osbadmin 427701 Apr 22 12:06 Success 123333 -rw-r--r-- 1 osbadmin osbadmin 427701 Apr 22 12:06 Success 123333 (1) [osbadmin@qa1 cp]$ it gives [osbadmin@qa1 cp]$ val="\""; ls -ltr | awk -v var=$val '{ORS=" ";print var $NF var; }' "1272" "(1)" "123333" "SANITY_TEST" "b" [osbadmin@qa1 cp]$ I have to get output as "a b" "SANITY_TEST" "Success 123333" "Success 123333 (1)" Please help me......... |
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Quote:
Code:
ls -ltr | sed '/^-/!d' | sed 's/\(.*\):\([0-9]*\) \(.*\)/\"\3\"/' | tr "\n" " " |
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Quote:
Thaks for your support.............. |
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