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04-21-2009
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multiple if conditions
Guys, Im trying to have a script that evaluates multiple conditions :
Code:
test.sh: if [ $1 = "brazil1" ] then echo "host $1" else if [ $1 = "brazil2" ] then echo "host $1" else echo $1 not valid exit 1 fi Code:
./test.sh brazil1 Code:
./test.sh: line 12: syntax error: unexpected end of file Thanks Last edited by bashshadow1979; 04-21-2009 at 01:32 PM.. |
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04-21-2009
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You have two 'if' and only one 'fi' if I saw this correctly. Use the code tag.
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04-21-2009
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Multiple conditions
Im sorry for not using the code tag, I will next time
What I'm trying to do is to have a script where I can send one parameter and based on that parameter execute a function. if the script received brazil1 then echo something, if it receives brazil2 then echo something else.. etc.. etc.. Thanks guys, I'm sorry for the dumb question but I cant figure it out.. |
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04-21-2009
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I don't see you put in the second 'fi' yet at the end so I'll change the second else to 'elif' for you:
Code:
if [ $1 = "brazil1" ]; then echo "host $1" elif [ $1 = "brazil2" ]; then echo "host $1" else echo $1 not valid exit 1 fi |
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04-21-2009
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Quote:
Code:
case $1 in "brazil1") # do this ;; "brazil2") # do that ;; *) # oops ;-) ;; esac |
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