Quote:

Originally Posted by cjnd1988 I am new to shell programming and have an assignment question which requires me to list the contents of the present working directory in 4 column format and highlight any subdirectories.

Homework assignments are not permitted here, but maybe this will get you started:

Code:

unset files
n=0
for file in *
do
  [ -d "$file" ] &&
     files[${#files[@]}]=$file/ ||
     files[${#files[@]}]=$file
done
w=$(( $COLUMNS / 4 - 1 ))
printf "%-$w.${w}s %-$w.${w}s %-$w.${w}s %-$w.${w}s\n" "${files[@]}"

With very few exceptions, scripts written for sh will run without modification in bash.

Please put code inside [code] tags.

#!/bin/sh

if [ -n "$1" ]
then
 WORKDIR=$1
else
 WORKDIR=`pwd`
fi

WORKDIR=`echo $WORKDIR | awk \
'{
  if (substr($0,length($0),1)=="/")
  {
   print substr($0,1,length($0)-1)
  } else {
   print $0
  }
 }'`

echo $WORKDIR

for DIR in `ls -l $WORKDIR | grep "^d" | awk '{ print $NF }'`
do
 echo "Found directory $DIR, Decend, List, Ignore (D,L,I) ?"
 read DLI
 DLI=`echo $DLI | tr "dli" "DLI"`
 case $DLI in
  "D" ) $0 $WORKDIR/$DIR;;
  "L" ) ls -l $WORKDIR/$DIR | grep -v "^d" | awk -v COUNTER=0 \
'{
  printf "%s ",$NF
  COUNTER++
  if (COUNTER>=5)
  {
   printf "\n"
   COUNTER=0
  }
 }' | column -t;;
  "I" ) echo "Ignored directory $DIR";;
 esac
done

ls -l $WORKDIR | grep -v "^d" | awk -v COUNTER=0 \
'{
  printf "%s ",$NF
  COUNTER++
  if (COUNTER>=5)
  {
   printf "\n"
   COUNTER=0
  }
 }' | column -t

Code:

echo "The present working directory is: $WORKDIR "
cd $WORKDIR

for directory in *
do
    (I am thinking the test will go in here to test the value of $directory)
    echo "Found directory $directory; do you want to Descend, List or Ignore:"
    read answer
    case $answer in
    "D") WORKDIR=$WORKDIR/$directory
           echo $WORKDIR
           exec ./tryc $WORKDIR;;
     "L") (this will call a function to list the contents of the directory);;
     "I") echo "The directory was ignored" ;;
     esac
done

Use test -d.

Code:

if [ -d "$directory" }
then
   echo "$directory is a directory"
else
   echo "$directory is not a directory"
fi

Or you can bypass the test altogether; this will only list directories:

Code:

for directory in */

Code:

#!/bin/bash



displaydir()

{
	n=0

	local alist=$( ls $1 )

	for file in $alist

	do

	[ -d "$file" ] &&

		files[${#files[@]}]=$file/ ||

		files[${#files[@]}]=$file

	done

	w=10
 #$(($COLUMNS/4-1))

	printf "%-$w.${w}s %-$w.${w}s %-$w.${w}s %-$w.${w}s\n" "${files[@]}"
	
}


#unset files

#unset answer



descenddir()

{
	local BASEDIR=$1

	local LOCALDIR="$PWD"


	echo "The present working directory is: $BASEDIR "

	cd $BASEDIR

	echo "Do you want to display the contents of this directory?"

	read answer

	case $answer in

	"Y") displaydir "$BASEDIR";;

	"N") ;;

	esac



	local dirlist=$( ls )

	for directory in $dirlist

	do

		if [ -d $directory ]
 
		then {

			echo "Found directory $directory; do you want to Descend, List or Ignore (D,L, I): "

			read answer

			case $answer in

			"D") descenddir "$BASEDIR/$directory/";;

			"L") displaydir "$BASEDIR/$directory/";;

			"I") echo "The directory was ignored" ;;

			esac
 
		}

		fi

	done

	cd $LOCALDIR

}



if [ $1 ]
 
   then descenddir $1
 
   else descenddir "$PWD"

fi