Hi all
I need to strip blank lines from the end of a file. I have searched and found topics on how to strip lines from the entirety of a file - however I need to limit this to only the last 3-4 lines.

Any ideas?

Thanks

__________________
Free Palestine

Here's one solution using awk, from www.experts-exchange.com:
Name the script something like yourScript and use it like this:

yourScript < yourFile > TMP_00
mv TMP_00 yourFile

Nice one, thanks.

__________________
Free Palestine

Heres a little gizmo from my collection, its crude (no param checking) but it works




#!/bin/bash
#linechomp , removes trailing lines from end of file
numlines=`eval "cat $2 | wc -l"`
let splithere="$numlines-$1"
cat $2 | head -$splithere > $3
cat $2 | tail -$1 | sed -e '/^$/d' >> $3

usage: linechomp n foo bar

n is 3 or 4 in your case

Oomberas code might be better though as this doesn't guarantee you wont get

Line of some stuff, blah blah blah
<blank line>
Line of some more stuff
<blank line>

as your last 4 lines

Here's the same solution as oombera's though written in a more awk-like and less C-like fashion. Note that I'm also changing the problem somewhat: This will trim trailing lines consisting only of blanks and tabs (i.e., apparently empty) as well as truly empty lines:
Invoke it the same way as oombera's code. If you want only the truly empty lines to be whacked off the end, just change the first test to length == 0.