Under what sh `scaley 27` is a numeric-parameter ?

jack2 · #1 (**permalink**) 04-01-2009

Hi,

this part of code comes from an example
in dialog utility.
Running it under /sh
the following error is generated

"
Error: Expected a numeric-parameter for --begin.
Use --help to list options.
"
Is this example is 6 years old only, I expect it to work finally.

Jack

ROWS="`cut $tempfile -f1 -d, | cut -f2 -d:`"
COLS="`cut $tempfile -f2 -d,`"
rm $tempfile

# account for widest labels
COLS=`expr $COLS - 30`

# Takes an integer, multiplies it for COLS, divides for 132
scalex() {
echo $[$1*$COLS/132]
}
scaley() {
echo $[$1*$ROWS/60]
}

$DIALOG --backtitle "$TITLE" --no-shadow \
--begin `scaley 27` `scalex 98`

cfajohnson · #2 (**permalink**) 04-01-2009

That should run in bash, but I'd fix it so that it will run in any POSIX shellL

Code:

# $tempfile format: ROWS:???,COLS
IFS=:, read x ROWS COLS < "$tempfile"

# account for widest labels
COLS=$(( $COLS - 30 ))

# Takes an integer, multiplies it for COLS, divides for 132
scalex() {
  echo $(( $1 * $COLS / 132 ))
}

scaley() {
  echo $(( $1 * $ROWS / 60 ))
}

jack2 · #3 (**permalink**) 04-03-2009

Quote:

Originally Posted by cfajohnson

That should run in bash, but I'd fix it so that it will run in any POSIX shellL

Code:

# $tempfile format: ROWS:???,COLS
IFS=:, read x ROWS COLS < "$tempfile"

# account for widest labels
COLS=$(( $COLS - 30 ))

# Takes an integer, multiplies it for COLS, divides for 132
scalex() {
  echo $(( $1 * $COLS / 132 ))
}

scaley() {
  echo $(( $1 * $ROWS / 60 ))
}

Thanks for your kindly reply.
Exactly, examples I test, are 5-10 years old, written for bash.
Successfully I have both shells installed.

Jack

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