I have tried to implement a while loop into the code but upon running the following code i am getting the errors:

./Assigntest: line 42: syntax error near unexpected token `done'
./Assigntest: line 42: `done'



The code is as follows:

#!/bin/bash
#Filename: Assignment Author: Luke Francis
quit=n
while [ "$quit" = "n" ]
do
clear
echo "OPERATOR ADMINISTRATIVE TOOL"
echo "Please enter your password:"
read password
if [ $password -eq 0600519 ]
then
clear
echo "1. User Information"
echo "2. Network Connectivity"
echo "3. Processes"
echo "4. System Information"
echo "5. Hardware Utilization"
echo "Which option do you require?"
read menunumber
case $menunumber in
1) echo "USER INFORMATION"
echo "1. Registered Users"
echo "2. Disk Usage"
echo "3. Last Logins"
echo "Q.Quit"
echo "Which option do you require?"
read menunumber2
case $menunumber2 in
1) awk -F: '{print $1}' /etc/passwd
echo "Hit the Enter Key to continue"
read junk;;
2) du
echo "Hit Enter Key to continue"
read junk;;
3) who
echo "Hit Enter Key to continue"
read junk;;
Q|q) quit=y;;
*) echo "INCORRECT PASSWORD"
"Assigntest" 43L, 925C written                                
lf1ect@star-gateway$ <0> ./Assigntest
./Assigntest: line 42: syntax error near unexpected token `done'
./Assigntest: line 42: `done'
lf1ect@star-gateway$ <2> vi Assigntest
read password
if [ $password -eq 0600519 ]
then
clear
echo "1. User Information"
echo "2. Network Connectivity"
echo "3. Processes"
echo "4. System Information"
echo "5. Hardware Utilization"
echo "Which option do you require?"
read menunumber
case $menunumber in
1) echo "USER INFORMATION"
echo "1. Registered Users"
echo "2. Disk Usage"
echo "3. Last Logins"
echo "Q.Quit"
echo "Which option do you require?"
read menunumber2
case $menunumber2 in
1) awk -F: '{print $1}' /etc/passwd
echo "Hit the Enter Key to continue"
read junk;;
2) du
echo "Hit Enter Key to continue"
read junk;;
3) who
echo "Hit Enter Key to continue"
read junk;;
Q|q) quit=y;;
*) echo "INCORRECT PASSWORD"
sleep 1
esac
done
echo "Thank you for using the Operator Administrative Tool."

you have embedded 'case'-s, but only one 'esac'.
Also next time use BB Codes when posting data/code samples - you'll increase the chances of your posts being answered - this is absolutely impossible to read/comprehend.

You have posted a part of a script from 'vi' and then the execution. This is impossible to read.
Post the entire script using BB Codes in one block AND then output you're getting. Maybe some good Samaritan will try to help you.
Good luck.

Looks like you've got an if statement without corresponding fi

Hi all,

I have a similar problem.
My script is like:

#!/bin/sh
FILENAME=$1
while read line do
if [[$line = *sometext*]] then echo $line fi
done < $FILENAME

And I get the error:

line 5: syntax error near unexpected token `done'
line 5: `done < $FILENAME


Would you please share any ideas about how to solve the problem?

while read line; do
..
if [[$line = *sometext*]]; then

if [[ $line = *sometext* ]]; then

Missed the blanks around the [[ ]]...you can figure out the other stuff.

Hi erenay,
i think you forgot a thousand of (") and( and spaces:

while read line do
if [[$line = *sometext*]] then echo $line fi
done < $FILENAME

must be:

while read line; do
if<space>[[<space>$line = *sometext*<space>]]; then echo "$line"; fi
done < $FILENAME

Bye