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03-19-2009
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Help with awk in array in while loop
Hi everyone
 I have 2 files - IN & OUT. Example: IN A:13:30 B:45:40 . . . UNLIMITED OUT Z:12:24 Y:20:15 . . . UNLIMITED I want first row of numbers of IN - OUT. Example 13-12 45-20 My code is #!/bin/csh -f set y=1 while ( $y<UNLIMITED ) set in = `awk -F':' '{print $2}' IN |awk '{array[NR]=$0} END {print array[y];}'` set out = `awk -F':' '{print $2}' OUT |awk '{array[NR]=$0} END {print array[y];}'` set number = `expr $in - $out` echo "$number" @ y = $y + 1 end expr: syntax error expr: syntax error expr: syntax error expr: syntax error expr: syntax error expr: syntax error all is expr: syntax error I tried to solve more than one day already.  And also duno wat should i write instead of UNLIMITED.Anyone can help me? |
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