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03-17-2009
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How to include shell scripts in one big shell script?
I am wanting to create one shell script which I run, as I want it to run a series of other shell scripts and PHP scripts in sequence. But, I am not sure how to include shell scripts. Note: Paths changed for security/aesthetic reasons. Code:
#!/bin/sh # FILE: '_final.sh' -- a list of shell scripts and php files to run. sh /path/to/delete.sh # # Just ignore these following lines for the moment #sh /path/to/mycronjobs/unzip.sh #php /path/to/mycronjobs/ci_cron.php --run=/cron/run/ --show-output #sh /path/to/mycronjobs/mysql_import.sh #php /path/to/mycronjobs/ci_cron.php --run=/cron/removeBlankRows/ --show-output The problem is that whenever I try to run this on the command line it complains that: Quote:
I've looked on Google, the most I got was that I am meant to either use the 'source' command or the '.' command, but without explanation of how to use it. I tried both of the following; Code:
#!/bin/sh . /path/to/delete.sh source /path/to/delete.sh But I still get the same result/error. Can someone enlighten me, how do I include the shell scripts? Is there an include function or something? Thanks. |
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