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Eliminating duplicates from the who command Eliminating duplicates from the who command
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Old 03-17-2009
mikejreading mikejreading is offline
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Unhappy Eliminating duplicates from the who command
I am trying to show how many users are logged into one of my systems. Using who -q it gives me a user count, but some users are logged in multiple times.

Is there any easy parameter that I can use to ignore/eliminate these duplicates??

Thanks
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Old 03-17-2009
gehlnar gehlnar is offline
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Can you try with who|uniq , see whether you are get rid of dups.

Cheers,
gehlnar
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Old 03-17-2009
mikejreading mikejreading is offline
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No... no joy :-(,

who|uniq outputted exactly the same as the who command without the pipe.
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Old 03-17-2009
Padow Padow is offline
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Code:
who | awk '{ print $1 }' | sort -u
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Old 03-17-2009
va2206 va2206 is offline
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Hi,

This one also can help.

who | awk '{print $1}' | uniq
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Old 03-17-2009
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Goldorakk Goldorakk is offline
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Code:
who | cut -f1 -d' ' | sort | uniq
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Old 03-17-2009
mikejreading mikejreading is offline
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Thanks, that has listed all the unique users, how would I then calculate the amount of users, like who -q shows #users... any thoughts?
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