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Replace a blank space with string "\\ "

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# 1  
Old 02-06-2009
Replace a blank space with string "\\ "
Hi,
I have a requirement to replace a every blank space with char "\\ ".
Like string "God Love" to "God\\ Love"
and "God Love" as "God\\ \\ Love".
and only in the sed.

We have already a script but it is replaceing all continuous blank space with one "\\ ". which is as
DIR=`sudo echo $INSTALL| cut -f1 -d'/'|sed 's/ /\(\\\)\(\\\)\(\\\)\(\\\) /g'|sed 's/(//g'|sed 's/)//g'`

here $INSTALL is as input .
# 2  
Old 02-06-2009
Code:
echo 'a  b' | sed 's/ /\\\\ /g'

# 3  
Old 02-06-2009
thanks,
but in my input i don't know how many blank space..
Should it work in that case also..

Also can u explane me the following line

DIR=`sudo echo $INSTALL| cut -f1 -d'/'|sed 's/ /\(\\\)\(\\\)\(\\\)\(\\\) /g'|sed 's/(//g'|sed 's/)//g'`
# 4  
Old 02-06-2009
Have you tried what'd been posted?
Last edited by vgersh99; 02-06-2009 at 04:00 PM..
# 5  
Old 02-06-2009
Not yer. I have not unix system at home. I will try it in office.
# 6  
Old 02-06-2009
I would appreciate if any one explain me these

DIR=`sudo echo $INSTALL| cut -f1 -d'/'|sed 's/ /\(\\\)\(\\\)\(\\\)\(\\\) /g'|sed 's/(//g'|sed 's/)//g'` Image
# 7  
Old 02-06-2009
The easiest way is to 'step' through the pipes one at the time:
Code:
$ echo 'a 1 2 3/b/c/d' | cut -f1 -d'/'
a 1 2 3

$ echo 'a 1 2 3/b/c/d' | cut -f1 -d'/' | sed 's/ /\(\\\)\(\\\)\(\\\)\(\\\) /g'
a(\)(\)(\)(\) 1(\)(\)(\)(\) 2(\)(\)(\)(\) 3


$ echo 'a 1 2 3/b/c/d' | cut -f1 -d'/' | sed 's/ /\(\\\)\(\\\)\(\\\)\(\\\) /g' | sed 's/(//g'
a\)\)\)\) 1\)\)\)\) 2\)\)\)\) 3


$ echo 'a 1 2 3/b/c/d' | cut -f1 -d'/' | sed 's/ /\(\\\)\(\\\)\(\\\)\(\\\) /g' | sed 's/(//g' | sed 's/)//g'
a\\\\ 1\\\\ 2\\\\ 3
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