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print specific lines

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# 1  
Old 02-03-2009
print specific lines
I have a text file made of different blocks separated by blank lines. I need to print the blocks with odd indexes. How can I get it with awk?
For example i need to print the first and the third block of a file like this:

asgdg sadsd ssgsdgd
ass uff fedd sddddso

ieeduydd dddee deeo
ssancnc chhdh cchdd

aasi askf fkf kff
sskkkk dddu dduu
# 2  
Old 02-03-2009
Try this:

Code:
awk 'NR%6<3' file

Regards
# 3  
Old 02-03-2009
Thanks, it works. Now i need to count the characters in each block in the file but only if the preceding block contain a specific expression in the first line.
Thanks in advance
Andrea Musella
# 4  
Old 02-03-2009
Please open a new thread if you have another question.
Post the input file and the expected output within code tags and give the exact conditions.

Regards
# 5  
Old 02-03-2009
hi
Hello Franklin i am also check ur coding.. it's working.. i appreciate u..
Last edited by Franklin52; 02-03-2009 at 08:43 AM.. Reason: url removed
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