tail | grep


 
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# 1  
Old 01-22-2009
tail | grep

The program that is running on my machine generates log files. I want to be able to know the number of lines that contain "FT" in the most recent log file. I wrote the following, but it always returns zero. And I know the count is not zero. Any ideas?

ls -rt *.log | tail -n 1 | grep -c FT
# 2  
Old 01-22-2009
you need to assign ls-rt *.log | tail -n 1 to a variable, then grep that.
add | wc -l to the end of it to get the count


a=
a=`ls -rt *.log | tail -n 1`
cat $a | grep "FT" | wc -l
# 3  
Old 01-22-2009
Code:
grep -c FT  $(ls -rt *.log | tail -n 1 )

# 4  
Old 01-22-2009
Just so I have something to work with, could you give me a few file names, and the contents of those files? or samples? I like to test my scripts before giving them as answers >_<

-- Ignore the above.. apparently the ninja unix users beat me to it :P

Last edited by Rhije; 01-22-2009 at 12:13 PM.. Reason: The ninjas won :(
# 5  
Old 01-22-2009
use
find with xarg and wc utility
# 6  
Old 01-22-2009
grep -e "FT" /path/to/log/dir/*.log | wc -l
# 7  
Old 01-22-2009
thanks guys. the following worked for me:

egrep -c FT `ls -rt *.log | tail -n 1`
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