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saving awk value in a bash array variable

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# 1  
Old 12-17-2008
saving awk value in a bash array variable
hi all i am trying to save an awk value into an array in bash:

Code:
total[$count]=`awk '{sum+=$3} END {print sum}' "$count".txt"`
((count++))

the above statement is in a while loop..
$count is to keep track of file numbers (1.txt,2.txt,3.txt,etc.)

i get the following error:

Code:
./lines1: command substitution: line 24: unexpected EOF while looking for matching `"'
./lines1: command substitution: line 25: syntax error: unexpected end of file

the awk statement works when i save it in a single variable but does not seem to work when i use an array.
what is wrong with this? any help appreciated.
# 2  
Old 12-17-2008
Code:
total[$count]=`awk '{sum+=$3} END {print sum}' ${count}.txt`;

You just have too many double quote.
Remove it and try again.
Cheers,Smilie
X
Last edited by eXedon; 12-17-2008 at 09:51 PM..
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