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# 1  
Old 11-18-2008
How to search (grep?) filename for a string and if it contains this then...
Hi i want to write a script that will search a filename e.g. test06abc.txt for a string and if it contains this string then set a variable equal to something:

something like:

var1=0

search <filename> for 06
if it contains 06 then
var1=1
else
var1=0
end if

but in unix script Smilie
# 2  
Old 11-19-2008
using find command followed by if condition
Hi try this

file=`find dirpath -type f -name "filename" -exec grep 06 {} \;`

if [ "$file" = "" ] ; then
var=0
else
var=1
fi
Last edited by mailme0712; 11-19-2008 at 05:04 AM..
# 3  
Old 11-19-2008
Hi! You can use grep for this.

Code:
check=`grep 06 FILENAME > /dev/null; echo $?`
if [ "$check" -eq "0" ]; then
var1=1
else
var1=0
fi

# 4  
Old 11-19-2008
Hi,

grep has the -q or --silent option for this. Try

Code:
grep -q "test" file && a=found || a=missing

which will set $a to found if "test" was found in file. Else $a will be set to missing.

HTH Chris
# 5  
Old 11-19-2008
When i search for a string in any file i use this:

Code:
find ./ -name "filename" | xargs grep "string_to_found"

In this way you can specify what kind of files are you searching for
"filename" or "file*" or "?ile_+.txt" or .....

it's clear and simple.
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